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 Ground bounce explanation - Am I right? 

Last post Fri, Oct 26 2012 7:23 AM by VLSI Learner. 0 replies.
Started by VLSI Learner 26 Oct 2012 07:23 AM. Topic has 0 replies and 557 views
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  • Fri, Oct 26 2012 7:23 AM

    Ground bounce explanation - Am I right? Reply
    My doubt: I am considering one circuit of a CMOS inverter with NMOS connected to an inductor, before it connects to a ground. When the PMOS is on, Vout= 1 (say 5 volt = '1' and 2 volt = '0') and when the NMOS is on, PMOS is off. At that time Vout will start to drain out through NMOS, consequently current will flow through inductor. say after time 't' the voltage across the inductor is V= L*di/dt At one time this will occur Vout = V and both are less than 5volt. Beyond that time a time will come when V will be slightly greater than Vout. At that time NMOS will swap it's source and drain. That means so far what was drain, will now be source. And V will start to drain through NMOS and it will add to Vout. This process will continue till NMOS is ON. And so Vout will never go to ground. This is ground bounce. Am I right?
    • Post Points: 5
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Started by VLSI Learner at 26 Oct 2012 07:23 AM. Topic has 0 replies.